Counting & Probability (Ex 10D)
Year 11 Mathematical Methods · Cambridge Methods 1&2, Counting Methods · Mr Wong
Learning intentions.
- Count total equally-likely outcomes for an arrangement or selection
- Count favourable outcomes using restrictions, "exactly" and "at least"
- Write each probability as an exact, simplified fraction
Key results
For equally-likely outcomes $P(\text{event})=\dfrac{n(\text{favourable})}{n(\text{total})}$.
Count both with the multiplication principle, $^nP_r$ or $^nC_r$, then simplify.
"At least one" is often quickest as $1-P(\text{none})$.
Warm-up — set up the fraction
1. The $5$ distinct letters of
MATHS are arranged at random.
a Total number of arrangements
b $P(\text{the word ends in }S)$
c $P(\text{the word starts with }M)$
Part A — Probability with arrangements
2. The digits $1,2,3,4,5$ are arranged at random to form a five-digit number.
a $P(\text{the number is even})$
b $P(\text{the number is greater than }30\,000)$
3. Four people line up at random. Find $P(\text{two particular people }A\text{ and }B\text{ stand together})$.
4. Four boys and three girls stand in a row at random. Find $P(\text{all four boys stand together})$.
(Glue the boys into a block.)