Applications in 3D (Ex 6E)
Year 10 Mathematics Core · Cambridge Ch 6, §6E · Mr Wong
Learning intentions.
- Find a right-angled triangle hidden inside a 3D object (cube, box, pyramid, mast)
- Redraw that triangle in 2D, sometimes using Pythagoras first to find a side
- Apply SOHCAHTOA to find an unknown length or angle, then report the answer in the 3D context
Key results — handy 3D Pythagoras shortcuts
Cube side $a$: face diag $=a\sqrt{2}$, space diag $=a\sqrt{3}$
Box $a\times b\times c$: base diag $=\sqrt{a^2+b^2}$, space diag $=\sqrt{a^2+b^2+c^2}$
Warm-up
1. A cube has side length $2$ m. With $A$ = front-bottom-left, $B$ = front-bottom-right, $C$ = back-bottom-right and $D$ = back-top-right:
a Exact face diagonal $AC=$
b Exact space diagonal $AD=$
c $\angle DAC=$ (1 d.p.)
d $\angle CAB=$
Part A — Mast and cables
2. A vertical mast is supported at the top by two cables to points $A$ and $B$ on opposite sides. The cable from $A$ is $36$ m at $48°$ to the horizontal; point $B$ is $24$ m from the base.
(a) Find the height of the mast (3 d.p.).
(b) Find the angle the $B$-cable makes with the horizontal (2 d.p.).
3. A $8$ m vertical pole is supported by four equal cables, each anchored $6$ m from the base of the pole (on the ground). Find
(a) the length of one cable, and
(b) the angle each cable makes with the ground (2 d.p.).
Part B — Boxes and prisms
4. A rectangular box has dimensions $3 \times 4 \times 5$ cm. Find:
a base diag (3 × 4) =
b space diag =
c angle between space diag and base = (2 d.p.)
5. A rectangular box has dimensions $2 \times 3 \times 6$ m. Find
(a) the length of the space diagonal (2 d.p.), and
(b) the angle this diagonal makes with the $2\times 3$ base (2 d.p.).