Logarithms (Ex 13E)

Year 11 Mathematical Methods Unit 1 · Cambridge §13E · Mr Wong

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Learning intentions.

Key results

$a^x=y \;\Longleftrightarrow\; \log_a(y)=x$  ($a>0,\;a\ne 1,\;y>0$)

Product: $\log_a(m)+\log_a(n)=\log_a(mn)$  |  Quotient: $\log_a(m)-\log_a(n)=\log_a(m/n)$

Power: $\log_a(m^p)=p\log_a(m)$  |  $\log_a(1)=0$, $\log_a(a)=1$

Part A — Exp / Log form swap

1. Rewrite each exponential statement in log form.
a $5^4=625$  
b $7^{-2}=\tfrac{1}{49}$  
c $\left(\tfrac{1}{3}\right)^3=\tfrac{1}{27}$  
d $10^0=1$  
2. Fill in the blanks.
a $\log_2(16)=$
b $\log_6(36)=$
c $\log_{10}\!\left(\tfrac{1}{1000}\right)=$
d $\log_5(\;\;\;)=3$, so arg $=$
e $\log_2(\;\;\;)=-1$, arg $=$
f $\log_{\;\;\;}(81)=2$, base $=$

Part B — Evaluating logarithms

3. Evaluate.
a $\log_2(8)=$
b $\log_3(9)=$
c $\log_{25}(5)=$
d $\log_{16}(2)=$
e $\log_2\!\left(\tfrac{1}{8}\right)=$
f $\log_3\!\left(\tfrac{1}{81}\right)=$
4. Evaluate (fractional answers).
a $\log_4(8)=$
b $\log_{27}(81)=$
c $\log_{25}\!\left(\tfrac{1}{5}\right)=$
d $\log_{81}\!\left(\tfrac{1}{3}\right)=$
5. Which of the following are undefined? Circle them.   $\log_2(-2)$  ·  $\log_2(0)$  ·  $\log_5(1)$  ·  $\log_{10}(0.001)$

Logarithms 13E — continued

Part C (laws of logs) · Part D (solve log equations)

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Part C — Laws of logarithms

Use the product / quotient / power laws to simplify.

6. Simplify (write your answer as a single number where possible).
a $\log_2(32)-\log_2(8)=$
b $\log_2(16)+\log_3(1)=$
c $2\log_9(9)-\log_9\!\left(\tfrac{4}{9}\right)=$
d $\log_2(5)+\log_2(x)=$
7. Write each as a single logarithm.
a $3\log_a(x)+\log_a(20)=$
b $2\log_2(x)-\log_2(x+5)=$
c $3\log_{10}(x^3y^6)-5\log_{10}(x)=$
d $\tfrac{1}{2}\log_7(x^4y^6)-2\log_7(y)=$
8. Change of base. Express $\log_2(8)$ in terms of base-$10$ logarithms and evaluate.  

Part D — Solving log equations

Combine logs, rewrite in exponential form, solve, then check the domain.

9. Solve for $x$.
a $\log_2(x)+\log_2(x+2)=3$   $x=$
b $\log_{10}(x+2)-\log_{10}(x)=2\log_{10}(4)$   $x=$
c $\log_5(x)+\log_5(x-4)=1$   $x=$
d $2\log_{10}(x)=\log_{10}(9)$   $x=$